A Gold ion with charge eQ has N = 197 Nucleons, Z = 79 Protons, and (Z-Q) electrons. (Here Q is an integer and e is the charge of a single proton.) The mass is m = au - Qm{sub e} + E{sub b}/c{sup 2} (1) where a = 196.966552 is the relative atomic mass [1, 2] of the neutral Gold atom, u = 931.494013 MeV/c{sup 2} is the unified atomic mass unit [3], and m{sub e}c{sup 2} = .510998902 MeV is the electron mass [3]. E{sub b} is the binding energy of the Q electrons removed from the neutral Gold atom. This amounts to 0.332 MeV for the helium-like gold ion (Q = 77) and 0.517 MeV for the fully stripped ion. For the Au{sup 31+} ion we have E{sub b} = 13.5 keV. These numbers are given in Ref. [4].

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